Because when it's sorting some of them as ints and some of them as strings. JavaScript has implicit conversion to string.
Wrong. JavaScript sort's default comparison function always converts to strings.
Only if one of them is a string right? If you have only numbers then it works fine right? Right? (Please say that I'm right ðŸ˜)
No. It always compares by converting to string. I actually think this is more consistent then having different behaviour if you have a string somewhere in your list.
Basically the default comparator is a.sort((a, b) => `${a}` < `${b}` ? -1 : 1).
Because when it's sorting some of them as ints and some of them as strings. JavaScript has implicit conversion to string.
Wrong. JavaScript sort's default comparison function always converts to strings.
Only if one of them is a string right? If you have only numbers then it works fine right? Right? (Please say that I'm right ðŸ˜)
No. It always compares by converting to string. I actually think this is more consistent then having different behaviour if you have a string somewhere in your list.
Basically the default comparator is
a.sort((a, b) => `${a}` < `${b}` ? -1 : 1).