`not di` does not seem to perform bitwise negation

qaz@lemmy.world to Programming@programming.dev – 15 points –

I've been trying to debug a program I'm working on and have managed to narrow it down to a single not statement. I fail to understand how this could fail. My current suspicion is the fact that I'm using a 16 bit (aka short) register. Should I even be using this?

Before not di 1101111110000000
Expected after not di 0010000001111111
Actually after not di 10000001111111

Code

.certain:
not di ; ← this line is the problem
bsf ax, di

GDB output

(gdb) p/t (short) $di $4 = 1101111110000000
(gdb) nexti
(gdb) p/t (short) $di $5 = 10000001111111
5

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Your result is correct, is just not displaying the leading zeros.

Thanks, I somehow completely missed that.

Do you perhaps know how to show the leading zeros?

I'm not great with gdb but I think using the x cmd shows them.

Yes, but that doesn't seem to work with registers