Billionaire grindsetStriker@lemmy.worldmod to Lemmy Shitpost@lemmy.world – 322 points – 10 months ago42Post a CommentPreviewYou are viewing a single commentView all commentsAverage doesn't mean that 50% are above it. That's what the median is forBut in this case it does, or at least it should, since the IQ scale is based on a normal distribution which is symmetric along the mean.Happy data scientist noisesDang, you are rightBut wouldn't a certain amount have the same ig right at the median, meaning less than half would actually be above (and also below)?It depends on if we assume a discrete or continuous distribution.Look at you with your above-median IQ.1 more...
Average doesn't mean that 50% are above it. That's what the median is forBut in this case it does, or at least it should, since the IQ scale is based on a normal distribution which is symmetric along the mean.Happy data scientist noisesDang, you are rightBut wouldn't a certain amount have the same ig right at the median, meaning less than half would actually be above (and also below)?It depends on if we assume a discrete or continuous distribution.Look at you with your above-median IQ.1 more...
But in this case it does, or at least it should, since the IQ scale is based on a normal distribution which is symmetric along the mean.Happy data scientist noisesDang, you are rightBut wouldn't a certain amount have the same ig right at the median, meaning less than half would actually be above (and also below)?It depends on if we assume a discrete or continuous distribution.
But wouldn't a certain amount have the same ig right at the median, meaning less than half would actually be above (and also below)?It depends on if we assume a discrete or continuous distribution.
Average doesn't mean that 50% are above it. That's what the median is for
But in this case it does, or at least it should, since the IQ scale is based on a normal distribution which is symmetric along the mean.
Happy data scientist noises
Dang, you are right
But wouldn't a certain amount have the same ig right at the median, meaning less than half would actually be above (and also below)?
It depends on if we assume a discrete or continuous distribution.
Look at you with your above-median IQ.