RulematicaLesDeuxBonsYeux@sh.itjust.works to 196@lemmy.blahaj.zone – 371 points – 8 months ago14Post a CommentPreviewHotTopNewOldVector calculusLinear algebra.Shader programming, except if you actually tried that it would just be all blackno no…he’s got a pointClearly a line segmentPlease justify mathematically why it is a line segment:You can tell it is because of the way that it isQuestion csnceled :Dfor a sec I was looking for a loss memeThis is actually true in Porter/Duff.<=> y ⊕ ╲ = ╳If this were a shader and the colors would be inverted, this would be true.Do it in CMY(K) or any other subtractive colour space and it's correct.
Vector calculusLinear algebra.Shader programming, except if you actually tried that it would just be all black
no no…he’s got a pointClearly a line segmentPlease justify mathematically why it is a line segment:You can tell it is because of the way that it isQuestion csnceled :D
Clearly a line segmentPlease justify mathematically why it is a line segment:You can tell it is because of the way that it isQuestion csnceled :D
Please justify mathematically why it is a line segment:You can tell it is because of the way that it isQuestion csnceled :D
If this were a shader and the colors would be inverted, this would be true.Do it in CMY(K) or any other subtractive colour space and it's correct.
Vector calculus
Linear algebra.
Shader programming, except if you actually tried that it would just be all black
no no…he’s got a point
Clearly a line segment
Please justify mathematically why it is a line segment:
You can tell it is because of the way that it is
Question csnceled :D
for a sec I was looking for a loss meme
This is actually true in Porter/Duff.
<=> y ⊕ ╲ = ╳
If this were a shader and the colors would be inverted, this would be true.
Do it in CMY(K) or any other subtractive colour space and it's correct.