I uh... might have forgotten the terminal condition, so feel free to report me for violating Rule 2 of this community - breaking the law! (of good sense):-P
If you have finitely many problems, after purchasing finitely many copies, there should only be one problem left. If this problem isn't solved with another copy, you're out of luck and have to come up with the solution yourself.
If you have infinitely many problems then you shouldn't complain, for you'll solve infinitely many problems per copy.
You missed an opportunity to phrase that as how you may have 99 problems, but the last one is still there :-).
Template for future use: [insert popular phrase] (best if improperly applied, claiming it is for "ironic" purposes), then [follow up with cat picture].
Sounds like a "Achilles and the tortoise" problem
Zeno's pair-a-books!
I bought n books and I only have 100/2^^n problems left.
So it's like Bitcoin mining, then, halving each time.
How'd you solve the last 25%?
Recursion.
I uh... might have forgotten the terminal condition, so feel free to report me for violating Rule 2 of this community - breaking the law! (of good sense):-P
If you have finitely many problems, after purchasing finitely many copies, there should only be one problem left. If this problem isn't solved with another copy, you're out of luck and have to come up with the solution yourself.
If you have infinitely many problems then you shouldn't complain, for you'll solve infinitely many problems per copy.
You missed an opportunity to phrase that as how you may have 99 problems, but the last one is still there :-).
Template for future use: [insert popular phrase] (best if improperly applied, claiming it is for "ironic" purposes), then [follow up with cat picture].
Sounds like a "Achilles and the tortoise" problem
Zeno's pair-a-books!
I bought n books and I only have 100/2^^n problems left.
So it's like Bitcoin mining, then, halving each time.